Fig.4 the JAVA program to calculate the electronic orbital of the helium.
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import java.util.Scanner;
class MathMethod {
public static void main(String[] args) {
Scanner stdIn=new Scanner(System.in); // input r1 and |E|
System.out.println("r1 between nucleus and electron 1 (MM) ?");
double r=stdIn.nextDouble();
System.out.println("total energy |E| in the herium (eV) ? ");
double E=stdIn.nextDouble();
double me=9.1093826e-31; double mp=1.67262171e-27;
double mn=1.67492728e-27;double nucle=2*mp+2*mn;
double rm=(2*me*nucle)/(2*(2*me+nucle));
double pai=3.141592653589793; double epsi=8.85418781787346e-12;
double h=6.62606896e-34; double ele=1.60217653e-19;
for (int i=1;i<100;i++) { // repeat until r1=initial r1+100
// calculation of initial VY from E and r1
double poten=-(2*ele*ele*2)/(4*pai*epsi*r)+(ele*ele)/(4*pai*epsi*2*r);
//vya= total E-potential energy
double vya=-(E*1.60217646e-19)-poten*1.0e14;
if (vya>0) {
// vyb=velocity from kinetic energy
double vyb=Math.sqrt(vya/me);
double VY=vyb*1.0e-8; // change m/sec to MM/SS
double prexx=r; double VX=0.0; double WN=0.0; double preyy=0.0;
double xx,yy,vk,preVY,preWN,midWN;
do {
xx=prexx+VX; yy=preyy+VY; //electron 1 position after 1SS
preVY=VY;preWN=WN ;
vk=VX*VX+VY*VY; //calculation of WN from VX,VY
// WN=WN+Eq(7)
WN=WN+(rm*vk*1.0e-6)/h;
//calculation of VX,VY from Coulomb force
double ra=Math.sqrt(prexx*prexx+preyy*preyy);
double rb=Math.sqrt(4.0*prexx*prexx+2.0*preyy*preyy);
ra=ra*1.0e-14; rb=rb*1.0e-14;
prexx=prexx*1.0e-14; preyy=preyy*1.0e-14;
double ac=(2*ele*ele)/(4*pai*epsi*rm);
// VX=VX+Eq(5-1)*10^(-30)
VX=VX+1.0e-30*ac*prexx*(-1.0/(ra*ra*ra)+1.0/(rb*rb*rb));
// VY=VY+Eq(5-2)*10^(-30)
VY=VY+1.0e-30*ac*preyy*(-1.0/(ra*ra*ra)+0.5/(rb*rb*rb));
prexx=xx;preyy=yy;
} while (xx>0); //repeat above until electron 1 arive at y axis
if (VY>-0.0001 && VY<0.0001) { // last VY condition
System.out.print("r1: "+r+" ");
System.out.printf("VX:%.5f ", VX);
System.out.printf("VY:%.5f ", VY);
System.out.printf("preVY:%.5f ", preVY);
midWN=(preWN+WN)/2; System.out.printf("midWN:%.5f \n", midWN);
}
} r=r+1;
}}}